$9v^2-w^2y^2$
$\:6=\frac{k\\:+\\:5}{2}\:$
$y''=0$
$9x^2+3x-14=0$
$\frac{dt}{dx}=\frac{2tx}{\left(t^2-x^2\right)}$
$\frac{500}{\left(1+0.1\right)^2}$
$\lim_{x\to1}\left(\frac{\sqrt{x-1}}{\left|x+1\right|}\right)$
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