$y=\frac{-x^2}{2}+8x$
$\frac{dy}{dx}-5y=\frac{-5xy^3}{2}$
$5x+12=4x+6$
$5x-12\le3x-4$
$\left(2y+6\right)^2$
$6x-3=x+17$
$8x^4-2x^2=0$
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