$\frac{\cos\:^2\left(x\right)\left(1+\sin\:^2\left(x\right)\right)}{\sin\:^4\left(x\right)}=\csc\:^4\left(x\right)-1$
$\frac{x^3-4x-10}{x^2-x-6}$
$\frac{x}{x^2-1}+\frac{1}{x^2-x-2}$
$6-2-10:5-11$
$\left(9a+5b\right)\left(8a+5b\right)$
$13x+3y-4z=21$
$\left(-x^2+8x-12\right)\left(-x^2+8x-12\right)$
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