$\int\frac{3}{x^2-5x+4}dx$
$128+\left(201\right)$
$\frac{x-x}{5\ge30}$
$\left(4a^3+3\right)\left(6a^3-7\right)$
$\int\left(x^3\cdot\left(x^4+1\right)^{-\frac{2}{3}}\right)dx$
$18\cdot25$
$x^2-10x+19=0$
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