Final answer to the problem
$\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nx^{\left(3+4n\right)}}{\left(3+4n\right)\left(2n\right)!}+C_0$
Got another answer? Verify it here!
Step-by-step Solution
Learn how to solve integrals of polynomial functions problems step by step online. Find the integral int(x^2cos(x^2))dx. Rewrite the function \cos\left(x^2\right) as it's representation in Maclaurin series expansion. Simplify \left(x^2\right)^{2n} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 2n. Bring the outside term x^2 inside the power serie. When multiplying exponents with same base we can add the exponents.
Final answer to the problem
$\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nx^{\left(3+4n\right)}}{\left(3+4n\right)\left(2n\right)!}+C_0$
