$58-5+12$
$\frac{x^2+3x+12}{x+4}$
$x^3+x^2-3x-4\:por\:8x^2+2x$
$\left(9-x^3\right)\left(9+x^3\right)$
$\left(4x\right)^3+\left(3y\right)^3$
$\left(5x^3+3\right)\left(2x^2-3x-1\right)$
$\frac{3}{5}z+1.2=z$
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