$\left(3\:x^4\right)^0$
$\int_0^1\left(x^2+2e^x-4\right)dx$
$\frac{16}{x+1}=\frac{24}{x-1}$
$\left(6^9\right)^{-5}$
$\int\frac{x^4+2x^2+2}{x^2+1}dx$
$3x^3+6x^2+9x$
$\int100x^3\sqrt{5x^4+3}dx$
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