$\left(x+2\right)\left(x-2\right)+\left(x+1\right)\left(x+4\right)$
$-6x-4x+5x+4-3+2$
$-7+\left(11\right)<7-\left(-6\right)$
$\sin\left(4x\right)\cos\left(9x\right)-\cos\left(4x\right)\sin\left(9x\right)=-\frac{3}{10}$
$-56+4$
$9x^2-12$
$-21\cdot\left(-8\right)$
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