Exercise
$\int sec^3\left(x\right)tan^4\left(x\right)dx$
Step-by-step Solution
Final answer to the exercise
$\frac{21}{16}\ln\left|\sec\left(x\right)+\tan\left(x\right)\right|+\frac{21}{16}\tan\left(x\right)\sec\left(x\right)+\frac{5}{24}\sec\left(x\right)^3\tan\left(x\right)+\frac{1}{6}\sec\left(x\right)^5\tan\left(x\right)-\frac{3}{4}\ln\left|\sec\left(x\right)+\tan\left(x\right)\right|-\frac{3}{4}\sec\left(x\right)\tan\left(x\right)-\frac{1}{2}\sec\left(x\right)^3\tan\left(x\right)-\frac{1}{2}\ln\left|\sec\left(x\right)+\tan\left(x\right)\right|+\frac{-\tan\left(x\right)\sec\left(x\right)}{2}+C_0$