$\frac{y^2dy}{dx}\:=\:\frac{1}{x^2}$
$\lim_{x\to0}\left(1+e^{\frac{4}{x}}\right)^x$
$\frac{2x^3-x^2-19x+15}{x-3}$
$5\cdot6+8$
$\lim_{x\to\infty}\left(\frac{\sqrt{16x+9}}{x+1}\right)$
$x^2-2x-10=0$
$\int\frac{1}{\left(x^2+4\right)\left(x^2+9\right)}dx$
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