$\lim_{x\to\infty}\left(\frac{x^2+1}{3^x}\right)$

$y\:=\:\ln\left(x^2-x-20\right)$

$\int\frac{x^3}{\sqrt[5]{6+x^4}}dx$

$16sen^4\left(x\right)-9=0$

$9v+9<\frac{5}{3}v-6$

$2y\frac{dy}{dx}\left(x\right)=18x^2$

$\lim_{x\to\infty}\left(\frac{\sqrt{x^2+1}}{\sqrt{x^2-1}}\right)^x$