$xy+\sqrt{1+x^2}\frac{dy}{dx}=0$
$\sqrt{9}-12$
$48.5\:=\:x\:.\:0.5\:+\:\frac{53.74\:-\:x\:.\:0.6\:}{0.4}.\:0.5$
$\frac{dy}{dx}=\frac{\left(xy+5x-y-5\right)}{\left(xy-2x+6y-12\right)}$
$4e^0$
$-7x\:-8y\:+12y\:+\:4x$
$ab+4a^2b^2$
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