$\left(b\right)\left(x+3\right)$
$6z-7-2z^2=0$
$-3\left(4x+2\right)+5x$
$\left(x^2+3x-6\right)\cdot\left(-3x^3\right)$
$4-2x<14$
$7-10-5+4+6-1$
$5x^2-22x+38=8x^2-40x+65$
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