$10x^2-5x-15$
$\frac{\left(-8\right)\left(-2\right)}{4}$
$\cos^2\left(x\right)\left(4\tan^3\left(x\right)+4\tan\left(x\right)\right)$
$\left(\frac{\left(2i-2\right)}{n}\right)^4$
$2x\:x\:2x$
$\frac{x^2+10}{2}=77$
$\left(16\cdot0.25\right)+\left(13\cdot0.2\right)+\left(0.3\cdot14\right)$
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