$\frac { ( x + 2 ) ^ { 3 } } { x + 2 }$
$\sec\left(x\right)=-\frac{3}{2}$
$-400+-300+-500+-300$
$y=\frac{8x-5}{6x-3}$
$\frac{d}{dx}tan4x^5$
$x^3+9x^2+24x+20$
$\left(y+4\right)\cdot\left(y^2-4y^2+16\right)$
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