$a^5b^3+a^2b^5$
$3x+1\ge-2+4x$
$sec^2\left(x\right)tan^2\left(x\right)+sec^2\left(x\right)=sec^4\left(x\right)$
$7-3n<13$
$12w^2-5w\:+20$
$\left(+25\right)-\left(-6\right)-\left(-22\right)+\left(+32\right)$
$\sqrt[3]{64a^5b^6}$
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