$x^2+6x=1$
$\left(-5\right)\left(-9\right)\left(-6\right)\left(-4\right)\left(-3\right)$
$dx\:+\:dy\cdot e^{6\cdot x}\:=\:0$
$\:t-6\:x\:3$
$5x^2+5x^3$
$\frac{-2cosx}{sinx}=-2cotx$
$\int\frac{\sqrt{x^2-36}}{x^6}dx$
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