$4r^2-2x+10-x^2+5x$
$x^2\left(2x-1\right)$
$525-\:\:-22$
$\lim_{x\to\infty}\left(\frac{\sqrt{16x^8-2x}}{x^4-1}\right)$
$\frac{1+\sin\left(x\right)}{\cos\left(x\right)^2}=\frac{1}{1-\sin\left(x\right)}$
$7x\left(x^2+9\right)$
$\left(-2\right)^{2}$
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