$- \frac { 9 x } { 3 x ^ { 2 } }$
$4\left(3\right)^2-9$
$x-5>0$
$-4x\:-\:6\:+\:x\:=\:-2x\:+\:x\:-\:10$
$\frac{dg}{dt}=6\left(1+2g\right)^{\frac{2}{3.0}}$
$\int\frac{1}{\sqrt{1-36x^2}}dx$
$\left(-4\right)+\left(-8\right)-\left(-6\right)-\left(-2\right)$
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