$\int\frac{x-3}{x^3-x}dx$
$-x^2-3x+14$
$\left(x^3-x^4\right)^2$
$5x-7=-7$
$\lim_{x\to0}\left(\frac{\left(tan\left(x\right)-x\right)}{\left(sin\left(x\right)-x\right)}\right)$
$\frac{dy}{dx}=x\cdot\sec\left(y\right)$
$\:7xy\:restar\:-8xy$
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