$\sqrt[3]{64a^3b^6}$
$\frac{x^2-4x+16}{4-x}$
$4x^2y^4-36x^4y^2$
$sen\left(a\right)tan\left(a\right)sec\left(a\right)+1=sec^2\left(a\right)$
$48\cdot\left(26+-36\right)$
$\sqrt{49\:x\:16}$
$\lim_{x\to0}\left(1-\sin\frac{x}{2}\right)^{\frac{1}{x}}$
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