$-7x^2+63=0$
$\left(x-3\right)\left(3=x\right)$
$\frac{x-9}{x^2+4x}$
$\frac{1}{\tan^2\left(a+1\right)}+\frac{1}{\cot2\left(a+1\right)}$
$-5r-4$
$=\frac{1}{-2x^2-6x-4}$
$\left(4n-3\right)^2$
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