$z+4\cdot z+4$
$y\left(x^2+49\right)=98$
$\frac{6.0451\cdot10^{12}}{\left(5.109\cdot10^{-15}\right)\left(5.472\cdot10^5\right)}$
$-6\:-\:\left(-8\right)$
$\left(5x^2+8x-3\right)+\left(2x^2-7x+13x\right)$
$\frac{8}{x-2}=\frac{5x-4}{x}$
$2\cdot26$
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