$\frac{ds}{dt}s=\left(6-t\right)\left(2+t^2\right)^{-1}$
$4h^2,\:16h^3,\:32h^4$
$\frac{dy}{dx}=4x-y$
$3^8:\left(-3\right)^4$
$97\cdot83$
$1-\left(1-sin^2x\right)$
$\frac { 3 x ^ { 3 } } { x + 1 } - x - 11$
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