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f(x)=sin(4x)^4cos(4x)^4−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫sin⁡(4x)4cos⁡(4x)4dx\int\sin\left(4x\right)^4\cos\left(4x\right)^4dx

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Final answer to the exercise

−sin⁡(4x)3cos⁡(4x)532−151024sin⁡(8x)−15128x+−5cos⁡(4x)3sin⁡(4x)256−164cos⁡(4x)5sin⁡(4x)+9512sin⁡(8x)+964x+3cos⁡(4x)3sin⁡(4x)128+C0\frac{-\sin\left(4x\right)^{3}\cos\left(4x\right)^{5}}{32}-\frac{15}{1024}\sin\left(8x\right)-\frac{15}{128}x+\frac{-5\cos\left(4x\right)^{3}\sin\left(4x\right)}{256}-\frac{1}{64}\cos\left(4x\right)^{5}\sin\left(4x\right)+\frac{9}{512}\sin\left(8x\right)+\frac{9}{64}x+\frac{3\cos\left(4x\right)^{3}\sin\left(4x\right)}{128}+C_0

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∫sin(4x)4cos(4x)4dx
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