$m^6-b^6$
$x^2\:+\:bx\:+\:c\:=\:\left(x\:-\:h\right)^2$
$2\sin\left(2x\right).\cos y=\frac{1}{2}$
$\left(7b^2d^6\right)^2$
$\sin\left(\frac{\pi}{2}-x\right)\sec\left(\frac{\pi}{2}-x\right)$
$\sin\left(x-\pi\right)=\tan\left(x\right)$
$\left(-7\right)^5\cdot\left(-7\right)^{12}$
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