$\left(+20\right)\:-\:\left(-45\right)\:\:$
$1-2\left(-3\right)+\left(3^2\right)$
$\left(5a+b\right)^3$
$6x^2-10x=-50$
$\int_4^{12}\left(\frac{10}{\sqrt{16x-x^2}}\right)dx$
$1020\cdot37$
$10r\:+\:42\:=\:-38$
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