$\left(3x^2+25\right)\left(3x^2+5\right)$
$\sqrt[2]{-34}$
$-23-\left(10+\left(-1\right)\right)-\left(-4\right)+\left|-2\right|$
$-xy+2x+3xy^2-4x-18y^2+3xy-6$
$-3+\tan=-3$
$2+x>16$
$8x^2+24x=0$
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