$e^3=y$
$\int\frac{\left(3x+5\right)^2}{\sqrt{x}}dx$
$\left(x^3+3x^2y+3xy^2+y^3\right)\left(8y^3\right)$
$\left(4m-1\right)^2$
$e^5=x+1$
$-5x-18\ge2\cdot\left(-4x+9\right)$
$\frac{d}{dx}\frac{\left(3x^2-7x\right)}{\left(x^2+2\right)^2}$
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