$x^2-3\left(x-4\right)^2$
$-4m+6\le-10$
$tg\left(x-\frac{3\pi}{2}\right)$
$5x^2+8x+1=0$
$\frac{sec\left(y\right)}{cos\left(y\right)}-\frac{tan\left(y\right)}{cot\left(y\right)}=1$
$\left(6m^2+3\right)\left(3m^2-2\right)$
$9x^2-5x=0$
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