$y^2\:\frac{dy}{dx}=1$
$\frac{\left(7x\:+15\right)}{\left(x^3-7x^2-18x\right)}$
$1-0,5$
$\frac{dy}{dx}=\frac{3x-4}{\left(5x+6\right)^4}$
$t^2+29-120$
$3x-4<7x-12$
$7ab+b$
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