(tan2x)tan2x+1\frac{\left(tan^2x\right)}{tan^2x+1}tan2x+1(tan2x)
f(x)=1x4+16f\left(x\right)=\frac{1}{x^4+16}f(x)=x4+161
cos(−x)(sec(x)−cos(x))=sin2(x)\cos\left(-x\right)\left(\sec\left(x\right)-\cos\left(x\right)\right)=\sin^2\left(x\right)cos(−x)(sec(x)−cos(x))=sin2(x)
(0.7−9a)(0.6−5a)\left(0.7-9a\right)\left(0.6-5a\right)(0.7−9a)(0.6−5a)
(y−7)(y4)\left(y^{-7}\right)\left(y^4\right)(y−7)(y4)
26+28\sqrt{26+28}26+28
7a2(−ab)7a^2\left(-ab\right)7a2(−ab)
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