$\left(5m^8+4\right)^2$
$y^'=\frac{6x-12}{x^2}$
$x\:+\:4\:=\:12$
$\lim_{x,y\to0,0}\left(\frac{sinx}{y}\right)$
$\frac{-4x^3+7x^2+x+4}{x^2\cdot\:\left(x+1\right)\cdot\:\left(x-5\right)}$
$5+5\cdot2+5\cdot3$
$\lim_{x\to1}\left(\frac{\ln\left(x\right)}{x^7-1}\right)$
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