$\int mgdg$

$\int\frac{6x}{\left(x-1\right)^2\left(x+2\right)^2}dx$

$64=4^x$

$\lim_{x\to0}\left(\frac{\cos\left(x\right)-x}{sin\left(x\right)-1}\right)$

$-\:\left\{-2\:-\:\left[-3\:-\:\left(-5\right)\:+1\right]\:-18\right\}$

$2a+8b-6c$

$\sin\:^{\left(2\right)}\theta\:=2\cos\:\theta\:+2$