$\frac{3x^3-10x+9}{x+2}$
$\lim_{x\to0}\left(\frac{\sqrt{3x+16}}{x}\right)$
$3+-1+4+-9$
$\frac{\left(x-1\right)}{3\:}=\frac{\left(x+4\right)}{2}$
$\log_{10}\left(x\right)=3.8$
$\left(3\cdot10^{-1}\right)\left(0.6\right)^2$
$\left(2x^2-6x\right)\left(3x-8\right)$
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