$\frac{28\cdot\left(32\cdot243\right)^2}{\left(3\cdot12\right)^4\cdot126}$

$\left(1+3ab^2c^3d^4\right)\left(1-3ab^2c^3d^4\right)$

$\left(6-3x+4\right)$

$3y'-5e^{2x}y=0;\:y\left(0\right)=1$

$v^2+4v+100$

$-\frac{24}{6}+\left(\frac{-3}{-3}\right)$

$y\frac{dy}{dx}=e^{2x-y^2}$