$$16x^2-8xc+c^2$$

$$\left(\left(\frac{1}{2}\right)xy\:\:-z^3\right)^2$$

$$\frac{x+5}{2x+6}>\frac{3}{2}$$

$$\frac{4}{x}-\frac{x}{2}=\frac{12}{x}$$

$$\frac{4x}{5x-1}+\frac{6}{3x+2}=\frac{2}{3}$$

$$3^0-3^4\cdot3^{-5}$$

$$2x\:+\frac{1}{2}x$$