Learn how to solve integrals of polynomial functions problems step by step online. Find the integral int((3x^2+1)^6)dx. We can expand the expression inside the integral \left(3x^2+1\right)^6 using Newton's binomial theorem, which is a formula that allow us to find the expanded form of a binomial raised to a positive integer n. The formula is as follows: \displaystyle(a\pm b)^n=\sum_{k=0}^{n}\left(\begin{matrix}n\\k\end{matrix}\right)a^{n-k}b^k=\left(\begin{matrix}n\\0\end{matrix}\right)a^n\pm\left(\begin{matrix}n\\1\end{matrix}\right)a^{n-1}b+\left(\begin{matrix}n\\2\end{matrix}\right)a^{n-2}b^2\pm\dots\pm\left(\begin{matrix}n\\n\end{matrix}\right)b^n. The number of terms resulting from the expansion always equals n + 1. The coefficients \left(\begin{matrix}n\\k\end{matrix}\right) are combinatorial numbers which correspond to the nth row of the Tartaglia triangle (or Pascal's triangle). In the formula, we can observe that the exponent of a decreases, from n to 0, while the exponent of b increases, from 0 to n. If one of the binomial terms is negative, the positive and negative signs alternate.. Expand the integral \int\left(729x^{12}+1458x^{10}+1215x^{8}+540x^{6}+135x^{4}+18x^2+1\right)dx into 7 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int729x^{12}dx results in: \frac{729}{13}x^{13}. The integral \int1458x^{10}dx results in: \frac{1458}{11}x^{11}.

Find the integral int((3x^2+1)^6)dx