$4e^5-2e^3$
$64y^2\:-\:48ya\:+\:9a^2$
$\int\left(\frac{2x}{1-x^3}\right)dx$
$\left(g^{-11}h^9\right)^7$
$\frac{x^3+4x^2+4x}{2-3x-2x^2};x=-2$
$\:\:3+\:8+2-\left(-4\right)\:-\left(-5\right)$
$\frac{e^{-t}}{t}$
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