$-y^2=x-3$
$\frac{dy}{dx}=3x^3y^2$
$16w^2+40wr^2+25^4$
$3x\left(2x^2+x\right)\left(3x+8\right)$
$15\cdot0\cdot2$
$\int\left(3\sec^2\left(3x\right)\right)dx$
$\frac{1}{\left(x+5\right)^2}$
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