$\int\frac{4y^3}{\sqrt[3]{2-5y^4}}dx$
$\sqrt{16}x^4$
$\left(3x-4y\right)\left(9x^2+12xy+16y^2\right)$
$x^2-2x+1+y^2-6y+9$
$\int x\left(x+9\right)^9dx$
$-6.\left(-8-4\right)$
$3\left(n\right)^2\left(\frac{2}{7}\right)$
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