$\cos\left(x\right)\tan\left(x\right)^2=\cos\left(x\right)$
$+126+452$
$\left(21-\frac{3}{4}q\right)\left(15-\frac{1}{4}q\right)$
$\left(x^3-x^2-x+2\right)\left(x-2\right)$
$x\left(x-1\right)=e$
$\int sec^2\left(6x+8\right)dx$
$\int_0^2e^{-2x}x\:dx$
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