$\left(-\:12\:+\:20\right)\::\:\left(-\:4\right)\:$
$\left(x^3y^a\right)^6$
$4y^2+29y+30=0$
$2\left(4x-3\right)+2=8x+4$
$\frac{dx}{dy}=6-\frac{3x}{50}$
$\frac{dy}{dx}=\frac{4x}{x^2+4}$
$\frac{1}{4}m^2+4$
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