$\int\frac{x^2+x+1}{x^5-x^4-x+1}dx$
$96x-8$
$-12+\left(49\right)-\left(-120-\left(-21\right)\cdot7\right)$
$\int\frac{3x^2+2}{\left(5-2x\right)^2\left(x^2+10x+26\right)}dx$
$-\frac{v}{9}=-35$
$\int\:5e^{0.01x}dx$
$y=x^{-\frac{3}{4}}$
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