$\frac{6x^3+5x^2-19x-10}{1}$
$\left(3x^3+2x\right)\left(3x^{2\:}-2x\right)$
$2x^2+3x-1\ge\:0$
$\left(ab^3-6\right)\left(ab^3+6\right)$
$14x^2y^2-27x^3+56x^4$
$dx+\left(2+x-y\right)dy=0$
$100-54$
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