$\int t^2e^{-.05t}dt$
$\frac{dy}{dx}=1+x$
$4x-2y=10$
$-\:16\:+\:\left(-10\right)\::\:\left(-2\right)$
$15\cdot14$
$\left(2x-2b\right)\left(2x+5y\right)$
$\sin\left(x\right)=-0.62$
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