$12.40\cdot14$
$\lim_{x\to\infty}\left(\frac{2x-1}{2x+5}\right)^{\left(\frac{2x+1}{3}\right)}$
$x^2+2x-3;\:x=-2$
$-6x+9<-2x+8$
$1-2x-x^2=0$
$\frac{8b\:-\:12a^4b^3\:-\:6a^5b^2\:+\:10a}{2ab^2}$
$\left(5x^3+4y^4\right)\left(5x^3-4y^4\right)$
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