$-\frac{9}{12}-\left(-\frac{7}{4}\right)$
$3x^2+12x-3=0$
$\left(124+23\right)-\left(-12+9\right)+123$
$2x^2-4x+3xy-6y$
$2\left(ab+ac+bc\right)$
$9xy+6xz+3x$
$10r\:+\:42\:=\:-38$
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