$\frac{dy}{dx}+2y^3x^3=0;\:\:\:\:\:y\left(1\right)=-2$
$\lim_{x\to-4}\left(-x\right)$
$\frac{x^2}{3}\cdot\frac{2x^5}{4}\cdot3$
$x\frac{dy}{dx}=\ln\left(x\right)$
$2xy\:+\:3xy$
$-6\left(8c-8\right)$
$-1=\frac{-x-2}{x^2-5x}$
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