$25x^2^2$
$t\left(x\right)=6x^2+13x+6x^2+26x+29y+28$
$ln\sqrt{1-x^5}$
$\int\frac{\left(\sqrt{x^2+25}\right)}{x}dx$
$xy'\:-\:2y\:=\:3x^2+2$
$6x+3=-33$
$\int x\:\sqrt{x^2-25\:}dx$
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